해저관로설계_The stability of the vortex shedding
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- 2008.12.28
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해저관로설계시 주어진 조건에 대한 The stability of the vortex shedding 계산입니다.
순차적으로 자세하게 나와 있습니다.
목차
Contents
Example1. The stability of the vortex shedding3
Condition. 3
Solution. 4 - 6
Example2. Then stable length? 7
Conclusion. 7
본문내용
The velocity of a moving fluid : 3ft/sec
Solution.
Re Number
= 3.5 X 105
Vortex shedding frequency
Here, Strouhal Number(S) is calculated by chart 3.21
When design the sea bottom pipe, mostly Strouhal Number is used 0.2
= 0.514cps
quency of span length
Here, Di is internal diameter.
Di = D 2t = 14inch 2 X 0.5 inch = 13inch
= 483.76 inch4
①EI = 3 X 107 X 483.76 inch4 = 1450 X 107 lb inch2
= 10.07 X 107 lb ft2
Sea bottom pipe weight Wa per unit length in the air condition.
Sea bottom pipe weight Ma per unit length.
= 2.24 Slug/ft
Supply mass
= 2.13 Slug/ft
Sea bottom pipe total weight M per unit length.
②M = 2.24 + 2.13 = 4.37 Slug/ft
According to
= 0.5323 cps
Safety investigation of Sea bottom pipe about Vortex shedding
Because of this condition is 0.366cps, pipe is not safe Vortex shedding
Example2. Then stable length?
∴ L ≤ 126.72 ft
Conclusion.
vortex shedding.
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